3x+3[4-3(2x+1)]=0

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Solution for 3x+3[4-3(2x+1)]=0 equation:


Simplifying
3x + 3[4 + -3(2x + 1)] = 0

Reorder the terms:
3x + 3[4 + -3(1 + 2x)] = 0
3x + 3[4 + (1 * -3 + 2x * -3)] = 0
3x + 3[4 + (-3 + -6x)] = 0

Combine like terms: 4 + -3 = 1
3x + 3[1 + -6x] = 0
3x + [1 * 3 + -6x * 3] = 0
3x + [3 + -18x] = 0

Reorder the terms:
3 + 3x + -18x = 0

Combine like terms: 3x + -18x = -15x
3 + -15x = 0

Solving
3 + -15x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -15x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -15x = 0 + -3
-15x = 0 + -3

Combine like terms: 0 + -3 = -3
-15x = -3

Divide each side by '-15'.
x = 0.2

Simplifying
x = 0.2

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